A) \[IAY\alpha \Delta T\]
B) \[AY\alpha \Delta T\]
C) \[\frac{AY}{\alpha \Delta T}\]
D) \[{{I}^{2}}Y\alpha \Delta T\]
Correct Answer: C
Solution :
Net change in length = 0 Thermal Exp. \[=I\propto \Delta t\] \[y=\frac{F/A}{\Delta l/l}\] \[\frac{\Delta l}{l}=\frac{F}{Ay}\] \[\frac{Fl}{Ay}=l\propto \Delta t\] \[F=Ay\propto \Delta t\]
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