JEE Main & Advanced JEE Main Paper (Held On 8 April 2017)

  • question_answer
    The maximum velocity of the photoelectrons emitted from the surface is v when light of frequency n falls on a metal surface. If the incident frequency is increased to 3n, the maximum velocity of the ejected photoelectrons will be -  [JEE Online 08-04-2017]

    A)  more than \[\sqrt{3}v\]              

    B)  equal to \[\sqrt{3}v\]

    C) \[v\]

    D)  less than \[\sqrt{3}v\]

    Correct Answer: B

    Solution :

    \[{{E}_{1}}=hn-\phi \] \[{{E}_{2}}=4hn-\phi \] \[{{E}_{2}}=3({{E}_{1}}+\phi )-\phi \] \[{{E}_{2}}=3{{E}_{1}}+2V\] \[{{m}_{0}}x\sqrt{3}y\]


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