A) \[S{{F}_{6}}\]
B) \[Br{{F}_{5}}\]
C) \[P{{F}_{5}}\]
D) \[{{[Cr{{F}_{6}}]}^{3-}}\]
Correct Answer: C
Solution :
\[S{{F}_{6}}=S{{p}^{3}}{{d}^{2}}\] \[Br{{F}_{5}}=S{{P}^{3}}{{d}^{2}}\] \[{{[Cr{{F}_{6}}]}^{3-}}=s{{p}^{3}}{{d}^{2}}\] \[PFs=s{{p}^{3}}d\]
You need to login to perform this action.
You will be redirected in
3 sec
