JEE Main & Advanced JEE Main Online Paper (Held on 9 April 2013)

  • question_answer
                    If a carrier wave \[c(t)=A\sin {{\omega }_{c}}t\] is amplitude modulated by a modulator single \[m(t)=A\sin {{\omega }_{m}}t\]then the equation of modulated signal \[\left[ {{C}_{\operatorname{m}}}\left( \operatorname{t} \right) \right]\]and its modulation index are respectively :                 JEE Main Online Paper (Held On 09 April 2013)

    A)                 \[{{C}_{\operatorname{m}}}\left( \operatorname{t} \right)=A(1+\sin {{\omega }_{m}}t)\sin {{\omega }_{c}}t\]and 2                   

    B)                 \[{{C}_{\operatorname{m}}}\left( \operatorname{t} \right)=A(1+\sin {{\omega }_{c}}t)\sin {{\omega }_{m}}t\]and 1                 

    C)                 \[{{C}_{\operatorname{m}}}\left( \operatorname{t} \right)=A(1+\sin {{\omega }_{m}}t)\sin {{\omega }_{c}}t\]and 1                

    D)                 \[{{C}_{\operatorname{m}}}\left( \operatorname{t} \right)=A(1+\sin {{\omega }_{c}}t)\sin {{\omega }_{m}}t\]and 2                

    Correct Answer: A

    Solution :

                    Modulation index \[=\frac{{{A}_{m}}}{{{A}_{c}}}=\frac{A}{A}=1\]                 Modulation signal will be                 As, \[{{C}_{m}}(t)=A(1+\sin {{\omega }_{m}}t)\sin {{\omega }_{c}}t\]                


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