JEE Main & Advanced JEE Main Online Paper (Held on 9 April 2013)

  • question_answer
                    If the ratio of lengths, radii and Young? module of steel and brass wires in the figure are a, b and c respectively, then the corresponding ration of increase in lengths is:                   JEE Main Online Paper (Held On 09 April 2013)

    A)                 \[\frac{3c}{2a{{b}^{2}}}\]                

    B)                 \[\frac{2{{a}^{2}}c}{b}\]                               

    C)                        \[\frac{3a}{2{{b}^{2}}c}\]                

    D)                 \[\frac{2ac}{{{b}^{2}}}\]                

    Correct Answer: C

    Solution :

                    For steel wire                    As change in length \[(\Delta {{l}_{1}})=\frac{3Mg{{l}_{1}}}{r_{1}^{2}\pi {{y}_{1}}}\]             ...(i)                 and for beam wire,                 Change in length  \[(\Delta {{l}_{2}})=\frac{2Mg\,{{l}_{2}}}{\pi r_{2}^{2}{{y}_{2}}}\]                          ...(ii)                 Dividing Eq. (i) by (ii), we get, r                 Corresponding ratio of increase in their lengths \[=\frac{3a}{2{{b}^{2}}c}\]                


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