A) HI is a strong reducing agent
B) H-I bond is too strong to be broken homiletically
C) I atom combines with H atom to back HI
D) Iodine atom is not reactive enough to add across a double bond
Correct Answer: D
Solution :
Addition of HI in the presence of peroxide catalyst does not follow anti-Markownikoff's rule because iodine radicals have tendency to form \[{{l}_{2}}\] molecule. \[{{l}^{\centerdot }}+{{l}^{\centerdot }}\xrightarrow{\,}\,{{l}_{2}}\]
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