A) \[2\sqrt{2}\]
B) 27
C) 36
D) 8
Correct Answer: B
Solution :
Magnetic at centre \[O=\frac{{{\mu }_{0}}ni}{2R}\] ?(i) Magnetic field at point, \[P=\frac{{{\mu }_{0}}ni{{R}^{2}}}{2{{[{{R}^{2}}+{{(2\sqrt{2}R)}^{2}}]}^{3/2}}}\] ?(ii) Dividing Eq. (i) by (ii), we get \[=\frac{{{\mu }_{0}}ni}{2R}\times \frac{2\,({{R}^{2}}+8{{R}^{2}})}{{{\mu }_{0}}ni{{R}^{2}}}=\frac{{{(9{{R}^{2}})}^{3/2}}}{{{R}^{3}}}\] \[={{(3)}^{3}}=27\]You need to login to perform this action.
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