question_answer

                Electrode potentials \[\left( {{E}^{0}} \right)\] are given below:                 \[{{\operatorname{Cu}}^{+}}+\operatorname{Cu}=+0.52V,\]                 \[F{{e}^{3+}}/F{{e}^{2+}}=+0.77V,\]                 \[\frac{1}{2}{{\operatorname{I}}_{2}}\left( s \right)/{{I}^{-}}=+0.54V,\]                                                 \[A{{g}^{+}}/Ag=+0.88V.\]                 Based on the above potentials, strongest oxidizing agent will be:                   JEE Main Online Paper (Held On 09 April 2013)

A)                 \[{{\operatorname{Cu}}^{+}}\]                

B)                 \[{{\operatorname{Fe}}^{3}}^{+}\]                

C)                 \[{{\operatorname{Ag}}^{+}}\]                

D)                 \[{{\operatorname{I}}_{2}}\]