A) \[5.1\times {{10}^{-5}}\operatorname{M}\]
B) \[7.1\times {{10}^{-8}}\operatorname{M}\]
C) \[4.1\times {{10}^{-5}}\operatorname{M}\]
D) \[8.1\times {{10}^{-7}}\operatorname{M}\]
Correct Answer: A
Solution :
Concentration of \[CO_{3}^{2-}\] ions \[=1.0\times {{10}^{-4}}M\] For precipitation \[{{K}_{sp}}\le \,[B{{a}^{2+}}]\,[CO_{3}^{2-}]\] Given, \[{{K}_{sp}}=5.1\times {{10}^{-9}}\] Hence, minimum concentration of \[B{{a}^{2+}}\] ions should be \[=\frac{{{K}_{sp}}}{[CO_{3}^{2-}]}=\frac{5.1\times {{10}^{-9}}}{1.0\times {{10}^{-4}}}=5.1\times {{10}^{-5}}M\]
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