A) Schiff's reagent
B) Tollen's reagent
C) \[{{\operatorname{I}}_{2}}/\]Alkali
D) Fehling's solution
Correct Answer: C
Solution :
\[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-H\xrightarrow{{{l}_{2}},\,NaOH}\,NaOH\,\,\,H-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-{{O}^{-}}+\underset{\begin{smallmatrix} \,\,\,\,\,\text{Iodoform} \\ \text{(Yellow}\,\text{ppt}\text{.)} \end{smallmatrix}}{\mathop{CH{{l}_{3}}}}\,\] Formaldehyde dors not form iodoform.
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