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JEE Main & Advanced JEE Main Online Paper (Held on 9 April 2013)

  • question_answer
                    By how many folds the temperature of a gas would increase when the root mean square velocity of the gas molecules in a container of fixed volume is increased from \[5\times {{10}^{4}}\operatorname{cm}/s\] to\[10\times {{10}^{4}}\] cm/s?                   JEE Main Online Paper (Held On 09 April 2013)

    A)                 Two                

    B)                 Three                

    C)                 Six                

    D)                 Four                      

    Correct Answer: D

    Solution :

                    Relation between root mean square velocity and temperature                 \[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\]                 \[{{v}_{rms}}\propto \,\sqrt{T}\]                 \[T\propto \,{{\left( {{v}_{rms}} \right)}^{2}}\]                 If v is doubled, T will be four times.                


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