A) 40
B) 41
C) 16
D) 32
Correct Answer: B
Solution :
Ladies = 2, old men = 2, young men = 4 Case I 1 lady, 1 old man, 2 young man \[{{=}^{2}}{{C}_{2}}{{\cdot }^{2}}{{C}_{1}}{{\cdot }^{4}}{{C}_{2}}=2\cdot 2\cdot 6=24\] Case II 2 ladies, 1 old man, 1 young man \[{{=}^{2}}{{C}_{2}}{{\cdot }^{2}}{{C}_{1}}{{\cdot }^{4}}{{C}_{2}}=1\cdot 2\cdot 4=8\] Case III 1 lady, 2 old man, 1 young man \[{{=}^{2}}{{C}_{1}}{{\cdot }^{2}}{{C}_{2}}{{\cdot }^{4}}{{C}_{1}}=2\cdot 1\cdot 4=8\] Case IV 2 lady, 2 old man, 0 young man \[{{=}^{2}}{{C}_{2}}{{\cdot }^{2}}{{C}_{1}}{{\cdot }^{4}}{{C}_{0}}=1\cdot 1\cdot 1=1\] \[\therefore \] Required noise of ways \[=24+8+8+1=41\]
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