JEE Main & Advanced JEE Main Paper (Held On 9 April 2017)

  • question_answer
    Four closed surfaces and corresponding charge distributions are shown below - Let the respective electric fluxes through the surfaces be \[{{\Phi }_{1}},\,{{\Phi }_{2}},\,{{\Phi }_{3}}\] and\[{{\Phi }_{4}}\]. Then - [JEE Online 09-04-2017]

    A)  \[{{\Phi }_{1}}>{{\Phi }_{2}}>{{\Phi }_{3}}>{{\Phi }_{4}}\]             

    B)  \[{{\Phi }_{1}}<{{\Phi }_{2}}={{\Phi }_{3}}>{{\Phi }_{4}}\]

    C)  \[{{\Phi }_{1}}>{{\Phi }_{3}};\,\,{{\Phi }_{2}}>{{\Phi }_{4}}\]

    D)  \[{{\Phi }_{1}}={{\Phi }_{2}}={{\Phi }_{3}}={{\Phi }_{4}}\]

    Correct Answer: D

    Solution :

                    Eq = same in all \[\Phi =\] Same


You need to login to perform this action.
You will be redirected in 3 sec spinner