question_answer

A parallel plate capacitor has\[1\mu F\] capacitance. One of its two plates is given\[+2\mu C\]charge and the other plate, \[+4\mu C\] charge. The potential difference developed across the capacitor is:- [JEE Main 8-4-2019 Afternoon]

A) 5V                               

B) 2V

C) 3V                   

D)   1V

Correct Answer: D

Solution :

Charges at inner plates are \[1\mu C\]and \[1\mu C\] \[\therefore \]Potential difference across capacitor \[=\frac{q}{c}=\frac{1\mu C}{1\mu F}=\frac{1\times {{10}^{-6}}C}{1\times {{10}^{-6}}Farad}=1V\]