JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Afternoon)

  • question_answer
    The calculated spin-only magnetic moments (BM) of the anionic and cationic species of \[{{[Fe{{({{H}_{2}}O)}_{6}}]}_{2}}\]and \[[Fe{{(CN)}_{6}}],\]respectively, are : [JEE Main 8-4-2019 Afternoon]

    A) 4.9 and 0                    

    B) 2.84 and 5.92

    C) 0 and 4.9        

    D) 0 and 5.92

    Correct Answer: C

    Solution :

    Complex is \[{{[Fe{{({{H}_{2}}O)}_{6}}]}_{2}}\,\,\,[Fe{{(CN)}_{6}}]\]
    Complexion Configuration No. of unpaired electrons Magnetic moment
    \[{{[Fe{{({{H}_{2}}O)}_{6}}]}^{2+}}\] \[t_{2g}^{4}e_{g}^{2}\] 4 4.9 BM
    \[{{[Fe{{(CN)}_{6}}]}^{4-}}\] \[t_{2g}^{6}e_{g}^{0}\] 0 0


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