question_answer

Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product? [JEE Main 8-4-2019 Afternoon]

A) \[{{F}_{3}}C-CH=C{{H}_{2}}\]  

B) \[Cl-CH=C{{H}_{2}}\]

C) \[C{{H}_{3}}O-CH=C{{H}_{2}}\]          

D) \[{{H}_{2}}N-CH=C{{H}_{2}}\]

Correct Answer: A

Solution :

Due to higher e- withdrawing nature of \[C{{F}_{3}}\]group. It follow anti markovnikoff product