A) \[\vec{r}\times (\hat{i}+\hat{k})+2=0\]
B) \[\vec{r}.(\hat{i}-\hat{k})-2=0\]
C) \[\vec{r}.(\hat{i}-\hat{k})+2=0\]
D) \[\vec{r}\times (\hat{i}-\hat{k})+2=0\]
Correct Answer: C
Solution :
Let the plane be \[\left( x+y+z1 \right)+\lambda \left( 2x+3y+4z5 \right)=0\] \[\Rightarrow \]\[(2\lambda +1)x+(3\lambda +1)y+(4\lambda +1)z-(5\lambda +1)=0\] \[\bot \]to the plane \[xy+z=0\] \[\Rightarrow \]\[\lambda =-\frac{1}{3}\] \[\Rightarrow \] the required plane is \[xz+2=0\]You need to login to perform this action.
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