JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Morning)

  • question_answer
    Water from a pipe is coming at a rate of 100 litres per minute. If the radius of the pipe is 5 cm, the Reynolds number for the flow is of the order of : (density of water \[=1000kg/{{m}^{3}},\]coefficient of viscosity of water = 1mPas) [JEE Main 8-4-2019 Morning]

    A) \[{{10}^{6}}\]                                 

    B) \[{{10}^{3}}\]

    C) \[{{10}^{4}}\]         

    D) \[{{10}^{2}}\]

    Correct Answer: C

    Solution :

    Reynolds Number\[=\frac{\rho \text{v}d}{\eta }\] Volume flow rate \[=\text{v}\times \pi {{r}^{2}}\] \[\text{v}=\frac{100\times {{10}^{-3}}}{60}\times \frac{1}{\pi \times 25\times {{10}^{-4}}}\] \[\text{v}=\frac{2}{3\pi }m/s\] Reynolds Number\[=\frac{{{10}^{3}}\times 2\times 10\times {{10}^{-2}}}{{{10}^{-3}}\times 3\pi }\] \[\simeq 2\times {{10}^{4}}\] order\[{{10}^{4}}\]             


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