A) \[HB{{O}_{2}}\] and \[{{H}_{3}}B{{O}_{3}}\]
B) \[{{H}_{3}}B{{O}_{3}}\]and \[{{B}_{2}}{{O}_{3}}\]
C) \[{{B}_{2}}{{O}_{3}}\]and \[{{H}_{3}}B{{O}_{3}}\]
D) \[{{B}_{2}}{{O}_{3}}\] and \[{{[B{{H}_{4}}]}^{-}}\]
Correct Answer: C
Solution :
\[{{B}_{2}}{{H}_{6}}+3{{H}_{2}}O\xrightarrow[{}]{{}}2{{H}_{3}}B{{O}_{3}}+3{{H}_{2}}\] \[{{B}_{2}}{{H}_{6}}+3{{O}_{2}}\xrightarrow[{}]{{}}{{B}_{2}}{{O}_{3}}+3{{H}_{2}}O\] Correct option : (c)
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