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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Morning)

  • question_answer
    Given that :\[E_{{{O}_{2}}/{{H}_{2}}O}^{0}=+1.23V,\]
    \[E_{{{S}_{2}}O_{8}^{2-}/SO_{4}^{2-}}^{0}=+2.05V\]
    \[E_{B{{r}_{2}}/B{{r}^{-}}}^{0}=+1.09V\]
    \[E_{A{{u}^{3+}}/Au}^{0}=+1.4V\]
    The strongest oxidizing agent is -
    [JEE Main 8-4-2019 Morning]

    A) \[{{O}_{2}}\]                        

    B) \[B{{r}_{2}}\]

    C) \[{{S}_{2}}O_{8}^{2-}\]              

    D) \[A{{u}^{3+}}\]     

    Correct Answer: C

    Solution :

    For strongest oxidising agent, standard reduction potential should be highest. Correct option: (c)


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