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JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Afternoon)

  • question_answer
    Molal depression constant for a solvent is \[4.0kg\,mo{{l}^{-1}}.\]The depression in the freezing point of the solvent for \[0.03\,mol\,k{{g}^{-1}}\]solution of \[{{K}_{2}}S{{O}_{4}}\]is : (Assume complete dissociation of the electrolyte)             [JEE Main 9-4-2019 Afternoon]

    A) 0.12 K             

    B) 0.36 K

    C) 0.18 K             

    D) 0.24 K

    Correct Answer: B

    Solution :

    \[{{K}_{f}}=4\,K-kg/mol\]           \[m=0.03\,mol/kg\]           \[i=3\]           \[\Delta {{T}_{f}}=i{{K}_{f}}\times m\]           \[\Delta {{T}_{f}}=3\times 4\times 0.03=0.36K\]


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