| (molar mass of \[KI=166g\,mo{{l}^{-1}}\]) |
A) 1.08
B) 1.48
C) 1.51
D) 1.35
Correct Answer: C
Solution :
\[\frac{\text{w}}{\text{w}}%=20\] 100 gm solution has 20 gm KI 80 gm solvent has 20 gm KI \[m=\frac{\frac{20}{166}}{\frac{80}{1000}}=\frac{20\times 1000}{166\times 80}=1.56\simeq 1.51mol/kg\]
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