JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Afternoon)

  • question_answer
    If the function f(x) = \[\left\{ \begin{align}   & a|\pi -x|+1,x\le 5 \\  & b|x-\pi |+3,x>5 \\ \end{align} \right.\]is continuous at \[x=5,\]then the value of \[ab\] is :-                                                                                             [JEE Main 9-4-2019 Afternoon]

    A) \[\frac{2}{5-\pi }\]

    B) \[\frac{2}{\pi -5}\]

    C) \[\frac{2}{\pi +5}\]               

    D) \[\frac{-2}{\pi +5}\]

    Correct Answer: A

    Solution :

                            \[a|\pi -5|+1=b|5-\pi |+3\]             \[a|(5-\pi )+1=b(5-\pi )+3\]             \[(a-b)(5-\pi )=2\]             \[a-b=\frac{2}{5-\pi }\]         


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