A) 0.55 Nm
B) 0.27 Nm
C) 0.38 Nm
D) 0.42 Nm
Correct Answer: B
Solution :
\[\left| {\vec{\tau }} \right|=\left| \bar{M}\times \bar{B} \right|\] \[\tau =NI\times A\times B\times \sin {{45}^{o}}\] \[\tau =0.27Nm\] Option [b]You need to login to perform this action.
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