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JEE Main & Advanced JEE Main Paper (Held On 09-Jan-2019 Evening)

  • question_answer
    A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns. The output power is delivered at 230 V by the transformer. If the current in the primary of the transformer is 5A and its efficiency is \[90%\], the output current would be: [JEE Main Online Paper (Held On 09-Jan-2019 Evening]

    A) 45 A      

    B) 35 A

    C) 25 A                

    D)               50 A

    Correct Answer: A

    Solution :

    \[{{V}_{in}}=2300\text{ }volt,\text{ }{{I}_{in}}=5A\] \[{{N}_{1}}=4000\] \[{{V}_{0}}=230\text{ }V\] \[\left( 2300\times 5 \right)\times \frac{90}{100}=\left( 230 \right)\times I\] \[I\,\,=\,\,\frac{50\,\times \,90}{100}\,\,\,=\,\,45\,A\]                                


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