A) 32
B) 36
C) 9
D) 18
Correct Answer: B
Solution :
\[Area=\frac{1}{2}\,\,h.\text{ }k=50\] \[h.\text{ }k=100\] \[h.\text{ }k={{2}^{2}}\,.\,{{5}^{2}}\] Total divisors \[=\left( 2+1 \right)\left( 2+1 \right)=a\] If \[h\,\,>\,\,0,\,\,k>0\] \[But\,\,\,\,\,\,\,\left. \begin{align} & h>0,\,\,\,\,k<0 \\ & h<0,\,\,\,\,\,k>0 \\ & h<0,\,\,\,\,\,k<0 \\ \end{align} \right\}\]all are possible so that total no. of positive case \[9+9+9+9=36\]You need to login to perform this action.
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