JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Afternoon)

  • question_answer
    When heat Q is supplied to a diatomic gas of rigid molecules, at constant volume its temperature increases by \[\Delta T.\]The heat required to produce the same change in temperature, at a constant pressure is : [JEE Main 10-4-2019 Afternoon]

    A) \[\frac{7}{5}Q\]         

    B) \[\frac{3}{2}Q\]

    C) \[\frac{5}{3}Q\]                                 

    D) \[\frac{2}{3}Q\]

    Correct Answer: A

    Solution :

    \[Q=n{{C}_{\text{v}}}\Delta T\]           \[Q'=n{{C}_{p}}\Delta T\]           \[\therefore \]\[\frac{Q'}{Q}=\frac{{{C}_{p}}}{{{C}_{\text{v}}}}\] For diatomic gas:\[\frac{{{C}_{p}}}{{{C}_{\text{v}}}}=\gamma =\frac{7}{5}\] \[Q'=\frac{7}{5}Q\]              


You need to login to perform this action.
You will be redirected in 3 sec spinner