JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Afternoon)

  • question_answer
    In \[L{{i}^{++}},\]electron in first Bohr orbit is excited to a level by a radiation of wavelength\[\lambda .\] when the ion gets excited to the ground state in all possible ways (including intermediate emissions), a total of six spectral lines are observed. What is the value of \[\lambda \]?
    (Given : \[h=6.63\times {{10}^{34\text{ }}}Js;c=3\times {{10}^{8}}m{{s}^{1}}\])
    [JEE Main 10-4-2019 Afternoon]

    A) 9.4 nm                        

    B) 12.3 nm

    C) 10.8 nm

    D) 11.4 nm

    Correct Answer: C

    Solution :

      \[\Delta E=\frac{hc}{\lambda }\] \[13.6\times 9-0.85\times 9=\frac{hc}{\lambda }\] \[\lambda =\frac{hc}{9\times (13.6-0.85)eV}\] \[=\frac{1240eV.nm}{9\times 12.75eV}\] \[\lambda =10.8nm\]              


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