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JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Afternoon)

  • question_answer
                The angles A, B and C of a triangle ABC are in A.P. and\[a:b=1:\sqrt{3}.\] If \[c=4\text{ }cm,\] then the area (in sq. cm) of this triangle is: [JEE Main 10-4-2019 Afternoon]

    A) \[4\sqrt{3}\]                            

    B) \[\frac{2}{\sqrt{3}}\]

    C) \[2\sqrt{3}\]    

    D) \[\frac{4}{\sqrt{3}}\]

    Correct Answer: C

    Solution :

    \[\angle B=\frac{\pi }{3},\] by sine Rule             \[\sin \,A=\frac{1}{2}\] \[\Rightarrow A={{30}^{o}},a=2,b=2\sqrt{3},c=4\] \[\Delta =\frac{1}{2}\times 2\sqrt{3}\times 2=2\sqrt{3}sq.\,cm\]                


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