A) \[S{{c}^{3+}}<T{{i}^{3+}}<T{{i}^{2+}}<{{V}^{2+}}\]
B) \[T{{i}^{3+}}<T{{i}^{2+}}<S{{c}^{3+}}<{{V}^{2+}}\]
C) \[S{{c}^{3+}}<T{{i}^{3+}}<{{V}^{2+}}<T{{i}^{2+}}\]
D) \[{{V}^{2+}}<T{{i}^{2+}}<T{{i}^{3+}}<S{{c}^{3+}}\]
Correct Answer: A
Solution :
\[T{{i}^{+2}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{2}}\] unpaired electrons = 2. spin only magnetic moment\[(\mu )=\sqrt{2(2+2)}\] \[=\sqrt{8}B.M\] \[T{{i}^{+3}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{1}}\] unpaired electrons = 1 \[\mu =\sqrt{1(1+2)}=\sqrt{3}B.M\] \[{{V}^{+2}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{3}}\] \[\mu =\sqrt{3(3+2)}=\sqrt{15}B.M\] \[S{{c}^{+3}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}\] \[\mu =0\]
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