JEE Main & Advanced JEE Main Paper (Held On 10 April 2015)

  • question_answer
    In a \[\Delta ABC,\frac{a}{b}=2+\sqrt{3}\]and \[\angle C={{60}^{o}}.\] Then the ordered pair \[(\angle A,\angle B)\]is equal to: JEE Main Online Paper (Held On 10 April 2015)

    A) \[({{105}^{o}},{{15}^{o}})\]                         

    B) \[({{45}^{o}},{{75}^{o}})\]

    C) \[({{15}^{o}},{{105}^{o}})\]                         

    D) \[({{75}^{o}},{{45}^{o}})\]

    Correct Answer: A

    Solution :

                    \[\frac{\sin A}{\sin B}=2+\sqrt{3}\] \[\frac{\sin \left( {{105}^{o}} \right)}{\sin \left( {{15}^{o}} \right)}=2+\sqrt{3}\] \[\frac{\cos {{15}^{o}}}{\sin {{15}^{o}}}=2+\sqrt{3}\]


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