A) 10.2 eV
B) 12.1 eV
C) 20.4 eV
D) 16.8 eV
Correct Answer: C
Solution :
Assuming perfectly inelastic collision for maximum loss in K.E. \[{{V}_{f}}=\frac{{{V}_{i}}}{2}\] \[\Rightarrow \,\,K.{{E}_{f}}=\frac{1}{2}(2m)\frac{V_{i}^{2}}{4}\Rightarrow \,\,K.{{E}_{f}}\frac{K{{E}_{i}}}{2}\] \[\Rightarrow \,\,loss=\frac{K{{E}_{i}}}{2}\,\,\Rightarrow \,\,\frac{K{{E}_{i}}}{2}\le 10.2ev\] \[\Rightarrow \,\,K.{{E}_{i}}\le 20.4ev\]
You need to login to perform this action.
You will be redirected in
3 sec
