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JEE Main & Advanced JEE Main Paper (Held On 10 April 2016)

  • question_answer
    Two stars are 10 light years away from the earth. They are seen through a telescope of objective diameter 30cm. The wavelength of light 600 nm. To see the stars just resolved by the telescope, the minimum distance between them should be (1 light year \[=9.46\times {{10}^{15}}\]m) of the order of:   JEE Main Online Paper (Held On 10 April 2016)

    A) \[{{10}^{8}}km\]                 

    B) \[{{10}^{6}}km\]

    C) \[{{10}^{11}}km\]                               

    D) \[{{10}^{10}}km\]

    Correct Answer: B

    Solution :

                 \[\theta =\frac{1,22}{D}\]              \[\frac{x}{10\,light\,year}=\frac{1.22\times 60\times {{10}^{-9}}}{30\times {{10}^{-2}}}\]              \[\frac{x}{10\,light\,year}=24.4\times {{10}^{-7}}\]              \[x=2.4\times {{10}^{-7}}\times 9.46\times {{10}^{15}}m\] \[23.08\times {{10}^{6}}km\]


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