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JEE Main & Advanced JEE Main Paper (Held On 10 April 2016)

  • question_answer
    Let \[P=\{\theta \,:\,\sin \theta -\cos \theta =\sqrt{2}\cos \theta =\sqrt{2}\cos \theta \}\]and \[Q=\{\theta :\sin +\cos \theta =\sqrt{2}\,\sin \theta \}\] be two sets. Then   JEE Main Online Paper (Held On 10 April 2016)

    A) \[Q\,\not\subset P\]                        

    B) \[P\,\not\subset Q\]

    C) \[P\subset Q\,\]and \[Q-P\ne \phi \]        

    D) P = Q

    Correct Answer: D

    Solution :

                 For Let P \[\sin \theta =\cos \theta (\sqrt{2}+1)\] \[(\sqrt{2}-1)\,\sin \theta =\cos \theta \] ....... (i)              For Let Q \[\cos \theta =(\sqrt{2}-1)\,\sin \theta \] ?.... (ii) (i) & (ii) are same P = Q


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