JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Evening)

  • question_answer
    The eye can be regarded as a single refracting surface. The radius of curvature of this surface is equal to that of cornea (7.8 mm). This surface separateds two media of refractive indices 1 and 1.34. Calculate the distance from the refracting surface at which a parallel beam of light will come to focus- [JEE Main Online Paper (Held On 10-Jan-2019 Evening]

    A) 2 cm                            

    B) 3.1 cm

    C) 4.0 cm

    D)                  1 cm

    Correct Answer: B

    Solution :

    \[\,\frac{{{\mu }_{r}}}{v}-\frac{{{\mu }_{i}}}{u}=\frac{{{\mu }_{r}}\,-\,\,{{\mu }_{i}}}{R}\] \[u=-\infty ;\,\,\,\,v=?;\,\,\,\,\,{{\mu }_{r}}=\,\frac{4}{3}\] \[R=+\,7.8\] \[\frac{4}{3v}\,-0\,=\,\frac{4/3-1}{7.8}\,=\,\frac{1}{3\times 7.8}\] \[v=+\,4\,\times \,7.8=31.2\text{ }mm=3.1\text{ }cm\]


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