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JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Evening)

  • question_answer
    A closed organ pipe has a fundamental frequency of 1.5 kHz. The number of overtones that can be distinctly heard by a person with this organ pipe will be (Assume that the highest frequency a person can hear is 20,000 Hz) [JEE Main Online Paper (Held On 10-Jan-2019 Evening]

    A) 4                                             

    B) 7     

    C) 6   

    D)                  5

    Correct Answer: C

    Solution :

     \[f=(2n-1)\,\frac{v}{4\ell }\] \[\frac{v}{4\,\ell }=\,1500\] \[f=\left( 2n-1 \right)\times 1500\] \[{{f}_{max}}\] for audible frequency = 20,000 \[(2n-1)\times 1500<20,000\] \[2n-1<\frac{200}{15}\] \[2n-1<\frac{40}{3}\] \[2n-1<13.33\] \[2n<14.33\] \[n<7.16\] \[n=7\] Number of overtone \[=n-1=7-1=6\]                   


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