JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Evening)

  • question_answer
    For the circuit shown below, the current through the Zener diode is-   [JEE Main Online Paper (Held On 10-Jan-2019 Evening]

    A) 5 mA                           

    B) zero

    C) 14 mA  

    D)                  9 mA

    Correct Answer: C

    Solution :

    \[{{V}_{1}}=120-50=70\] \[I\times 5\times {{10}^{3}}=70\] \[I=14\text{ }mA\] \[{{V}_{1}}=50={{I}_{1}}\times 10\times {{10}^{3}}\] \[{{I}_{1}}=5\,mA\] \[{{I}_{2}}=I-{{I}_{1}}=14-5=9\,\,mA\]


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