A) \[4264.4\,\,\pm \,\,81.0\text{ }c{{m}^{3}}\]
B) \[4264\,\,\pm \,\,81c{{m}^{3}}\]
C) \[4300\,\,\pm \,\,80\text{ }c{{m}^{3}}\]
D) \[4260\,\,\pm \,\,80\text{ }c{{m}^{3}}\]
Correct Answer: D
Solution :
\[V=\frac{\pi {{D}^{2}}h}{4}\] \[V=\frac{\pi }{4}\times {{\left( 12.6 \right)}^{2}}\times 34.2\] \[V=4262.229\] Answer should be in three significant numbers As D & h. ?both have 3 significant figures \[\therefore \,\,\,V=4260\] \[\frac{dV}{V}=2\frac{dD}{D}+\frac{dh}{h}\] \[dV\,=\,\left[ 2\times \frac{0.1}{12.6}+\frac{0.1}{34.2} \right]\,\times \,4260\] \[dV=80\] \[\therefore \,\,\,V=4260\,\,\pm \,\,80\,c{{m}^{3}}\]
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