A) \[11\times {{10}^{-5}}\text{ }W\]
B) \[11\times {{10}^{-3}}\text{ }W\]
C) \[11\times {{10}^{5}}\text{ }W\]
D) \[11\times {{10}^{-}}^{4}W\]
Correct Answer: A
Solution :
\[{{i}^{2}}R=p\] \[4\times {{10}^{-6}}\times R=4.4\] \[R=1.1\times {{10}^{6}}\,\Omega \] \[P=\frac{{{11}^{2}}}{R}\] \[=\,\,\,\frac{11\times 11\times 10}{11\times {{10}^{6}}}\,=\,11\times {{10}^{-5}}\]
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