A) \[\frac{19}{36}\]
B) \[\frac{15}{72}\]
C) \[\frac{13}{36}\]
D) \[\frac{19}{72}\]
Correct Answer: D
Solution :
Sum of number of dice is 7 (1, 6), (2, 5), (3, 4) (6, 1), (5, 2), (4, 3) Sum of number of dice is 8 (2, 6), (3, 5), (4, 4), (6, 2), (5, 3) \[P\left( \overset{sum}{\mathop{7\,\,o}}\,r\text{ }8 \right)=\frac{11}{36}\] (Head + dice sum 7 or 8) (tail 1 + 7 or 8 appear) \[P\left( A \right)=\frac{1}{2}\left( \frac{11}{36} \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\frac{1}{2}\left( \frac{2}{9} \right)\] \[=\,\,\,\frac{11}{72}+\frac{1}{9}=\frac{19}{72}\]
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