JEE Main & Advanced JEE Main Paper (Held On 11 April 2014)

  • question_answer
    Given \[F{{e}^{3+}}(aq)+{{e}^{-}}\to F{{e}^{2+}}(aq);{{E}^{0}}=+0.77V\] \[A{{l}^{3+}}(aq)+3{{e}^{-}}\to Al(s);{{E}^{0}}=-1.66V\] \[B{{r}_{2}}(aq)+2{{e}^{-}}\to 2B{{r}^{-}};{{E}^{0}}=+1.09V\] Considering the electrode potentials, which of the following represents the correct order of reducing power?   [JEE Main Online Paper ( Held On 11 Apirl  2014 )

    A) \[F{{e}^{2+}}<Al<B{{r}^{-}}\]     

    B) \[B{{r}^{-}}<F{{e}^{2+}}<Al\]

    C) \[Al<B{{r}^{-}}<F{{e}^{2+}}\]     

    D) \[Al<F{{e}^{2+}}<B{{r}^{-}}\]

    Correct Answer: D

    Solution :

    Reducing character decreases down the series. Hence the correct order is \[Al<F{{e}^{2+}}<B{{r}^{-}}\]


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