A) \[{{N}_{2}}>O_{2}^{-}>{{O}_{2}}\]
B) \[O_{2}^{-}>{{O}_{2}}>{{N}_{2}}\]
C) \[N_{2}^{{}}>{{O}_{2}}>O_{2}^{-}\]
D) \[{{O}_{2}}>O_{2}^{-}>N_{2}^{{}}\]
Correct Answer: C
Solution :
The bond order of \[{{N}_{2}},{{O}_{2}},\]and \[O_{2}^{-}\] are respectively 3, 2 and 1.5 Since higher bond order implies higher bond dissociation energy hence the correct order will be\[{{N}_{2}}>{{O}_{2}}>O_{2}^{-}\]
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