JEE Main & Advanced JEE Main Paper (Held On 11 April 2014)

  • question_answer
    Consider the coordination compound, \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}.\]In the formation of this complex, the species which acts as the Lewis acid is:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )

    A) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]

    B) \[C{{l}^{-}}\]

    C) \[C{{o}^{3+}}\]                 

    D) \[N{{H}_{3}}\]

    Correct Answer: A

    Solution :

    \[\underset{\begin{smallmatrix}  Lewis \\  acid \end{smallmatrix}}{\mathop{C{{o}^{3+}}+}}\,\underset{\begin{smallmatrix}  Lewis \\  base \end{smallmatrix}}{\mathop{6N{{H}_{3}}}}\,\xrightarrow[{}]{{}}{{\left[ Co\underset{adduct}{\mathop{{{\left( N{{H}_{3}} \right)}_{6}}}}\, \right]}^{3+}}\]                


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