JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

  • question_answer
    The value of the resistor, \[{{R}_{S}},\]needed in the dc voltage regulator circuit shown here, equals : [JEE Main Online Paper (Held On 11 April 2015)]  

    A) \[({{V}_{i}}-{{V}_{L}})/n\,{{I}_{L}}\]

    B) \[({{V}_{i}}+{{V}_{L}})/n\,{{I}_{L}}\]

    C) \[({{V}_{i}}-{{V}_{L}})/(n+1)\,{{I}_{L}}\]

    D) \[({{V}_{i}}+{{V}_{L}})/(n+1)\,{{I}_{L}}\]

    Correct Answer: C

    Solution :

      Voltage drop across zener diode is \[{{V}_{L}}\]so voltage drop across S \[{{K}_{s}}\] \[{{K}_{Rs}}={{V}_{i}}-{{V}_{L}}=\left( n+1 \right){{I}_{L}}{{R}_{s}}\] \[{{K}_{s}}=\frac{{{V}_{i}}-{{V}_{L}}}{\left( n+1 \right){{I}_{L}}}\]


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