A) \[{{x}^{2}}+{{y}^{2}}-2x-2y-2=0\]
B) \[{{x}^{2}}+{{y}^{2}}-2x-2y-14=0\]
C) \[{{x}^{2}}+{{y}^{2}}-2x-2y+2=0\]
D) \[{{x}^{2}}+{{y}^{2}}-2x-2y-7=0\]
Correct Answer: B
Solution :
In an equilateral triangle in centre & circumcenter all same & R = 2r Now, \[r=\frac{\left| 3+4+3 \right|}{\sqrt{9+16}}\] =2 \[\Rightarrow \] \[R=4\] \[\therefore \]Equation of circumcircle is \[{{\left( x-1 \right)}^{2}}+{{\left( y+1 \right)}^{2}}=16\] \[\Rightarrow \]\[{{x}^{2}}+{{y}^{2}}-2x-2y-14=0\]You need to login to perform this action.
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