JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

  • question_answer
    The sum of the 3rd and the 4th terms of a G.P. is 60 and the product of its first three terms is 1000. If the first term of this G.P. is positive, then its 7th term is : [JEE Main Online Paper (Held On 11 April 2015)]  

    A)  7290

    B)  320

    C)  640

    D)  2430

    Correct Answer: B

    Solution :

      \[a{{r}^{2}}+a{{r}^{3}}=60\] &\[a\times ar\times a{{r}^{2}}=1000\] \[\Rightarrow \]\[ar\left( r+{{r}^{2}} \right)=60\]\[\Rightarrow \]\[{{a}^{3}}{{r}^{3}}=1000\] \[\Rightarrow \]\[ar=10\]\[\Rightarrow \]\[r+{{r}^{2}}=6\]\[\Rightarrow \]\[r=-3,2\] \[\Rightarrow \]\[r=2\]\[\Rightarrow \]\[a=5\] \[{{T}_{7}}=a{{r}^{6}}\] \[=5\times {{2}^{6}}\] \[=320\]


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