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JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

  • question_answer
    From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m/s. The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration \[g=32\text{ }m/{{s}^{2}},\]is: [JEE Main Online Paper (Held On 11 April 2015)]  

    A)  100

    B)  88

    C)  128

    D)  112

    Correct Answer: A

    Solution :

      \[{{v}^{2}}-{{u}^{2}}=2gh\] \[0-{{\left( 48 \right)}^{2}}=2\left( -32 \right)h\]\[\Rightarrow \]\[h=\frac{2304}{64}\]=36 \[\therefore \]The greatest height \[=64+36=100\] meters


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