[JEE Main Online Paper (Held on 11-jan-2019 Evening)]
A) 6V
B) 3 V
C) 2 V
D) 1 V
Correct Answer: C
Solution :
Potential difference between A and B = Potential difference between C and D \[=\frac{({{\varepsilon }_{1}}/{{r}_{1}})+({{\varepsilon }_{2}}/{{r}_{2}})+({{\varepsilon }_{3}}/{{r}_{3}})}{\frac{1}{{{r}_{1}}}+\frac{1}{{{r}_{2}}}+\frac{1}{{{r}_{3}}}}=\frac{1+2+3}{3}=\frac{6}{3}=2V\]
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