A) 1.8
B) 2.2
C) 1.6
D) 2.0
Correct Answer: A
Solution :
\[{{K}_{2}}Hg{{I}_{4}}\rightleftharpoons 2{{K}^{+}}+HgI_{4}^{2-}\] \[i=\frac{1+(n-1)\alpha }{1}\] \[i=\frac{1+(3-1)0.4}{1}=1.8\]
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