A) 12.0 h
B) 9.0 h
C) 7.2h
D) 18.0 h
Correct Answer: D
Solution :
For zero order reaction, \[{{t}_{1/2}}=\frac{{{a}_{0}}}{2k}\] \[k=\frac{{{a}_{0}}}{2{{t}_{1/2}}}=\frac{0.2}{2\times 6}=1.67\times {{10}^{-2}}mol\,{{L}^{-1}}{{h}^{-1}}\] \[{{A}_{t}}={{A}_{0}}-kt\] \[0.2=0.5-1.67\times {{10}^{-2}}t\] \[t=\frac{0.3}{1.67\times {{10}^{-2}}}=18h\]
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